The complexity of the proper orientation number

A proper orientation of a graph G=(V,E) is an orientation D of E(G) such that for every two adjacent vertices v and u, dD−(v)≠dD−(u) where dD−(v) is the number of edges with head v in D. The proper orientation number of G is defined as χ→(G)=minD∈Γmaxv∈V(G)dD−(v) where Γ is the set of proper orienta...

Full description

Saved in:
Bibliographic Details
Published in:Information processing letters Vol. 113; no. 19-21; pp. 799 - 803
Main Authors: Ahadi, A., Dehghan, A.
Format: Journal Article
Language:English
Published: Amsterdam Elsevier B.V 01-09-2013
Elsevier Sequoia S.A
Subjects:
Online Access:Get full text
Tags: Add Tag
No Tags, Be the first to tag this record!
Description
Summary:A proper orientation of a graph G=(V,E) is an orientation D of E(G) such that for every two adjacent vertices v and u, dD−(v)≠dD−(u) where dD−(v) is the number of edges with head v in D. The proper orientation number of G is defined as χ→(G)=minD∈Γmaxv∈V(G)dD−(v) where Γ is the set of proper orientations of G. We have χ(G)−1⩽χ→(G)⩽Δ(G), where χ(G) and Δ(G) denote the chromatic number and the maximum degree of G, respectively. We show that, it is NP-complete to decide whether χ→(G)=2, for a given planar graph G. Also, we prove that there is a polynomial time algorithm for determining the proper orientation number of 3-regular graphs. In sharp contrast, we will prove that this problem is NP-hard for 4-regular graphs. •We study the computational complexity of the proper orientation number.•We show that, it is NP-complete to decide whether χ→(G)=2, for a given planar graph G.•Also, we prove that there is a polynomial time algorithm for determining the proper orientation number of 3-regular graphs. In sharp contrast, we will prove that this problem is NP-hard for 4-regular graphs.
Bibliography:ObjectType-Article-2
SourceType-Scholarly Journals-1
ObjectType-Feature-1
content type line 23
ISSN:0020-0190
1872-6119
DOI:10.1016/j.ipl.2013.07.017