Can One Bind Three Electrons with a Single Proton?
Of course not for an ideal H – – atom. But with the help of an intense homogeneous magnetic field B , the question deserves to be reconsidered. It is known (see, e.g. Baumgartner et al. in Commun Math Phys 212(3):703–724, 2000; Brummelhuis and Duclos in J Math Phys 47:032103, 2006) that as B → ∞ and...
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Published in: | Few-body systems Vol. 45; no. 2-4; pp. 173 - 177 |
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Main Authors: | , , , |
Format: | Journal Article |
Language: | English |
Published: |
Vienna
Springer Vienna
01-05-2009
Springer Nature B.V |
Subjects: | |
Online Access: | Get full text |
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Summary: | Of course not for an ideal H
– –
atom. But with the help of an intense homogeneous magnetic field
B
, the question deserves to be reconsidered. It is known (see, e.g. Baumgartner et al. in Commun Math Phys 212(3):703–724, 2000; Brummelhuis and Duclos in J Math Phys 47:032103, 2006) that as
B
→ ∞ and in the clamped nucleus approximation, this ion is described by a one-dimensional Hamiltonian
where
N
= 3,
Z
= 1 is the charge of the nucleus, and
δ
stands for the well known “delta” point interaction. We present an extension of the “skeleton method” (Cornean et al. in Few-Body Syst 38(2–4):125–131, 2006; Proc Symp Pure Math AMS 77:657–672, 2008) to the case of three degree of freedom. This is a tool, that we learn from Rosenthal (J Chem Phys 35(5):2474–2483, 1971) for the case
N
= 2, which reduces the spectral analysis of (1) to determining the kernel a system of linear integral operators acting on the supports of the delta interactions. As an application of this method we present numerical results which indicates that (1) has a bound state for
Z
= 1 and
N
= 3. |
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ISSN: | 0177-7963 1432-5411 |
DOI: | 10.1007/s00601-009-0018-7 |