Can One Bind Three Electrons with a Single Proton?

Of course not for an ideal H – – atom. But with the help of an intense homogeneous magnetic field B , the question deserves to be reconsidered. It is known (see, e.g. Baumgartner et al. in Commun Math Phys 212(3):703–724, 2000; Brummelhuis and Duclos in J Math Phys 47:032103, 2006) that as B → ∞ and...

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Bibliographic Details
Published in:Few-body systems Vol. 45; no. 2-4; pp. 173 - 177
Main Authors: Bressanini, D., Brummelhuis, R., Duclos, P., Ruamps, R.
Format: Journal Article
Language:English
Published: Vienna Springer Vienna 01-05-2009
Springer Nature B.V
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Summary:Of course not for an ideal H – – atom. But with the help of an intense homogeneous magnetic field B , the question deserves to be reconsidered. It is known (see, e.g. Baumgartner et al. in Commun Math Phys 212(3):703–724, 2000; Brummelhuis and Duclos in J Math Phys 47:032103, 2006) that as B → ∞ and in the clamped nucleus approximation, this ion is described by a one-dimensional Hamiltonian where N  = 3, Z  = 1 is the charge of the nucleus, and δ stands for the well known “delta” point interaction. We present an extension of the “skeleton method” (Cornean et al. in Few-Body Syst 38(2–4):125–131, 2006; Proc Symp Pure Math AMS 77:657–672, 2008) to the case of three degree of freedom. This is a tool, that we learn from Rosenthal (J Chem Phys 35(5):2474–2483, 1971) for the case N  = 2, which reduces the spectral analysis of (1) to determining the kernel a system of linear integral operators acting on the supports of the delta interactions. As an application of this method we present numerical results which indicates that (1) has a bound state for Z  = 1 and N  = 3.
ISSN:0177-7963
1432-5411
DOI:10.1007/s00601-009-0018-7